RE: FD10 Filter Question

["Keith Doxey" <ukha@xxxxxxx>]

Are you saying you have this....

MCB1 - CU1 - CU2 - CU3- CU4- MCB2 ?????

That is not a ring !!!! That is a circuit fed from two breakers which can
be
severly overloaded without tripping and even it one trip pops the circuit
is
still live.

The only reason for a ring main is to allow 18A cable to be used on a 32A
trip. The theory being that because it is a ring the current will be shared
equally by both cables at about 16A each.

There is no advantage in using a 2.5mm ring instead of a 6mm single cable.

Why not do this

MCB1 - CU1 - CU2
MCB2 - CU3 - CU4

Wherever you fit the filter it will block interference and X10 so you would
need this

MCB1 - Filter - CU1 - CU2 - CU3 - CU4

or better still

Big MCB - Filter - CU0 fitted with 4 MCB's to feed each of the other
consumer units.

Anything anywhere else in the house would not get X10 from the stuff on
your
consumer units.

Keith

> -----Original Message-----
> From: geraint@xxxxxxx [mailto:geraint@xxxxxxx]
> Sent: 12 August 2001 18:29
> To: ukha_d@xxxxxxx
> Subject: [ukha_d] FD10 Filter Question
>
>
> Hi,
>
> Question on the FD10.
> I have the following setup on comsumer units :-
>
> The Main Household consumer unit feeding four more 20-way consumer
> units in node 0.
>
> I have the node 0 consumer units running from two MCB's from the main
> house unit in a ring circuit, so that the first feed hits consumer
> unit 1, then loops to 2, 3 and 4. 4 then has a return feed back to
> the main household one.
>
> Question is, where should I put the FD10 ?
> Do I need to put one in unit 1 and unit 4, as 2 and 3 could take
> power from number 4 bypassing the filter. Or even a filter per unit ?
>
> I do suffer minor interference from neighbours, but nothing major.
>
> Maybe i'm not understanding the filter properly.
> Any ideas, suggestions ?
>
> Thanks as always.
>
> Geraint.
>
>
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