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Re: OT VB question
- To: ukha_d@xxxxxxx
- Subject: Re: OT VB question
- From: "Dr John Tankard" <john@xxxxxxx>
- Date: Fri, 01 Jun 2001 10:02:35 -0000
- Delivered-to: rich@xxxxxxx
- Delivered-to: mailing list ukha_d@xxxxxxx
- Mailing-list: list ukha_d@xxxxxxx; contact
ukha_d-owner@xxxxxxx
- Reply-to: ukha_d@xxxxxxx
--- In ukha_d@y..., "Keith Doxey" <ukha@d...> wrote:
> If you just want to remove or replace a particular character which
is what I
> guess you are trying to do with a varaiable called
"StripStr" why
not use
> the Replace function.
>
> Replace(expression, find, replacewith[, start[, count[, compare]]])
>
> MyString = Replace("XXpXXPXXp", "p",
"Y") ' A binary
comparison starting at
> the beginning
> ' of the
string. Returns "XXYXXPXXY".
> MyString = Replace("XXpXXPXXp", "p",
"Y",1)' A textual comparison
starting
> at position 3.
> '
Returns "YXXYXXY". 3, -1, 1)
>
> Keith
Thanks
John
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